Viewing file:  display_create_table.lib.php (2.35 KB) -rw-rw-rw-
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<?php
/* vim: set expandtab sw=4 ts=4 sts=4: */
/**
* Displays form for creating a table (if user has privileges for that)
*
* for MySQL >= 4.1.0, we should be able to detect if user has a CREATE
* privilege by looking at SHOW GRANTS output;
* for < 4.1.0, it could be more difficult because the logic tries to
* detect the current host and it might be expressed in many ways; also
* on a shared server, the user might be unable to define a controluser
* that has the proper rights to the "mysql" db;
* so we give up and assume that user has the right to create a table
*
* Note: in this case we could even skip the following "foreach" logic
*
* Addendum, 2006-01-19: ok, I give up. We got some reports about servers
* where the hostname field in mysql.user is not the same as the one
* in mysql.db for a user. In this case, SHOW GRANTS does not return
* the db-specific privileges. And probably, those users are on a shared
* server, so can't set up a control user with rights to the "mysql" db.
* We cannot reliably detect the db-specific privileges, so no more
* warnings about the lack of privileges for CREATE TABLE. Tested
* on MySQL 5.0.18.
*
* @version $Id: display_create_table.lib.php 11986 2008-11-24 11:05:40Z nijel $
* @package phpMyAdmin
*/
if (! defined('PHPMYADMIN')) {
exit;
}
/**
*
*/
require_once './libraries/check_user_privileges.lib.php';
$is_create_table_priv = true;
?>
<form method="post" action="tbl_create.php"
onsubmit="return (emptyFormElements(this, 'table') && checkFormElementInRange(this, 'num_fields', '<?php echo str_replace('\'', '\\\'', $GLOBALS['strInvalidFieldCount']); ?>', 1))">
<fieldset>
<legend>
<?php
if ($GLOBALS['cfg']['PropertiesIconic']) {
echo '<img class="icon" src="' . $pmaThemeImage . 'b_newtbl.png" width="16" height="16" alt="" />';
}
echo sprintf($strCreateNewTable, PMA_getDbLink());
?>
</legend>
<?php echo PMA_generate_common_hidden_inputs($db); ?>
<div class="formelement">
<?php echo $strName; ?>:
<input type="text" name="table" maxlength="64" size="30" />
</div>
<div class="formelement">
<?php echo $strNumberOfFields; ?>:
<input type="text" name="num_fields" size="2" />
</div>
<div class="clearfloat"></div>
</fieldset>
<fieldset class="tblFooters">
<input type="submit" value="<?php echo $strGo; ?>" />
</fieldset>
</form>
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